can any1 help me solve for a and b (qn in attachment
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Originally Posted by amath9 can any1 help me solve for a and b (qn in attachment $\displaystyle \sqrt{3} - 2=2a\sqrt{3} +\frac{2b}{3} $ $\displaystyle \sqrt{3} = 2a\sqrt{3}$ and $\displaystyle -2 = \frac{2b}{3} $ solve this two equations $\displaystyle 2a=1 $ $\displaystyle -6 = 2b $
Its called comparing coefficients
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