10x^2-3x-3= A(x^2+1)+(Bx+C) (x-1)

find A B C

y=kx-5

y=6x-x^2-6

solve for k

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- Jun 12th 2009, 08:33 PMamath9polynomials
10x^2-3x-3= A(x^2+1)+(Bx+C) (x-1)

find A B C

y=kx-5

y=6x-x^2-6

solve for k - Jun 12th 2009, 09:48 PMAmer

the factors which multiply with in the right side should equal to the factor of in the left side so you will have

and the factors which are multiply with x in the right side should equal to the factor with x in the left side so you will have

and finally the terms with no x in the right side should equal to the terms with no x in the left side so you will have this

now you have three equation with three variables so you can solve them

find the sum of the second and the third

find the sum of this and the first one

the rest for you - Jun 13th 2009, 03:43 AMHallsofIvy
Multiply out the right side: .

In order that these be equal**for all x**, corresponding coefficients must be equal: 10= A+ B, -3= C- B, and -3= -C. Solve for A, B, and C.

Quote:

y=kx-5

y=6x-x^2-6

solve for k