Expression 1:
My Work:
The only answer choices I have for this self test are
Answer:
Expression 2:
The author states the correct answer for expression 2 is , and yes they say "x" not "y"....either way not sure how to arrive at this answer either.
This is a self teaching algebra book, however the author decided to not show her work in any of the chapter reviews which is frustrating.
Thanks again!
You state that this is the problem:
and that this is the answer:
Something is wrong, because the problem, as you wrote it, doesn't simplify to that answer. Part of the confusion is whether the problem is supposed to be this:The only answer choices I have for this self test are
Answer:
or this:
See the difference? Amer assumes you meant Eq.1b, and it does simplify to the answer you wrote above.
You will need to double-check to see if you copied down the problem and answer correctly before we can proceed. If the problem is supposed to be Eq.1a, then yes, you would simplify by rationalizing the denominator. But if the problem is supposed to be Eq.1b, then you just need to rewrite using negative & fractional exponents.
01
If we pretend that the problem was Eq.1a:
When rationalizing the denominator, you only deal with the 5th root of 5. You don't need to touch the x or y^2 because they are not underneath the radical sign:
But the problem is actually Eq.1b:
If you really want to rationalize the denominator, it would go like this:
See how messy it is, compared to the answer given?
01
I just do not clearly see how these examples coincide with
For instance wouldnt the in this case seems like it should be the , instead its 1 and im not sure how you choose that.
And in the other example you use the 3 as m. I assume because every exponent under the root is a 3.
anyway I think with my example I made it more harder
I mistake in the second example
ok lats solve it in other way
since any n root you can write it like this
if it was in the denominator or if it was in the numentor like this
ok
now the improtant step
since any fraction for any a
a can be
a can be anything ploynomial or function anything ..
then if you can simplify it is ok like this
it is clear or not ?