Just deleted my working

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June 12th 2009, 05:52 AM
Joel

Just deleted my working

I accidentally just deleted some working and cannot get it back.

Can you help me with this please.

Factor fully: ( a² - b² - c² )² - 4b²c²

= (a²-b²-c²)² - (2bc)²
= (a² - b² - c² - 2bc)(a² - b² - c² + 2bc)
= (a² - (b + c)²)(a² - (b – c)²)
=
=
= (a-b-c)(a+b+c)(a-b+c)(a+b-c)
June 12th 2009, 05:58 AM
alexmahone

Quote:

Originally Posted by Joel

I accidentally just deleted some working and cannot get it back.

Can you help me with this please.

Factor fully: ( a² - b² - c² )² - 4b²c²

= (a²-b²-c²)² - (2bc)²
= (a² - b² - c² - 2bc)(a² - b² - c² + 2bc)
= (a² - (b + c)²)(a² - (b – c)²)
= (a-(b+c))(a+(b+c))(a-(b-c))(a+(b-c))
= (a-b-c)(a+b+c)(a-b+c)(a+b-c)

Missing working has been colored in red.
June 12th 2009, 05:59 AM
Amer

Quote:

Originally Posted by Joel

I accidentally just deleted some working and cannot get it back.

Can you help me with this please.

Factor fully: ( a² - b² - c² )² - 4b²c²

= (a²-b²-c²)² - (2bc)²
= (a² - b² - c² - 2bc)(a² - b² - c² + 2bc)
= (a² - (b + c)²)(a² - (b – c)²)
=
=
= (a-b-c)(a+b+c)(a-b+c)(a+b-c)

$(a^2 - (b+c)^2)(a^2-(b-c)^2)$

$\left[(a-(b+c))(a+(b+c))\right]\left[(a-(b-c))(a+(b-c))\right]$

$(a-b-c)(a+b+c)(a-b+c)(a+b-c)$

someone is faster than me .......
June 12th 2009, 06:15 AM
Joel

Thanks Guys

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