No, they are not. If you plug either or into the original equation:
you get 8 = 0, so neither solution works.
However, if your original equation was supposed to be
then yes, those two solutions work. In fact, it makes solving this equation much easier, as you can solve it by factoring by grouping:
Set each factor equal to zero:
(the two real solutions)
(two non-real solutions)
(two more non-real solutions)
So it looks like you copied the problem wrong?
01
oh thanks a lot .. nope , i copied it down correctly .. i think its the book's mistake
Btw i hv a question here .. For questions like this where the leading coefficient is not 1 , is it a must for me to reduce the coefficient to 1 before i find the factors : example in this case
, is this step necessary
Before i start substituting the factors of the constant term to find the factors of the equation .
THanks .