The sum of 4 consecutive integers is -38. What are the numbers? Write & solve an equation. Can someone just help me with the equation? I'd appreciate it :]
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Originally Posted by ohhhxlex The sum of 4 consecutive integers is -38. What are the numbers? Write & solve an equation. Can someone just help me with the equation? I'd appreciate it :] Solve x + (x + 1) + (x + 2) + (x + 3) = -38 for x.
Originally Posted by ohhhxlex The sum of 4 consecutive integers is -38. What are the numbers? Write & solve an equation. Can someone just help me with the equation? I'd appreciate it :] If n is an integer then $\displaystyle n+(n+1)+(n+2)+(n+3)=-38 \iff 4n+6=-38 \iff 4n=-44 \iff n =-11$ So we get $\displaystyle -11,-10,-9,-8$ Edit too slow
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