Originally Posted by
AlderDragon This just confuses me. I am asked to solve these division problems using long division. I know how to do them normally, but long division confuses me.
$\displaystyle \frac{x^3+2x^2+3x-6}{x-1}$
and
$\displaystyle \frac{n^3-27}{n-3}$
Any ideas?
Hi AlderDragon,
$\displaystyle \frac{n^3-27}{n-3}=$
Use zeros to hold the places for the terms that are left out.
Code:
n^2 + 3n + 9
______________________
n - 3 | n^3 + 0n^2 + 0n - 27
(-) n^3 - 3n^2
------------
3n^2 + 0n
(-) 3n^2 - 9n
----------
9n - 27
(-) 9n - 27
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