This just confuses me. I am asked to solve these division problems using long division. I know how to do them normally, but long division confuses me.

$\displaystyle \frac{x^3+2x^2+3x-6}{x-1}$

and

$\displaystyle \frac{n^3-27}{n-3}$

Any ideas?

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- Jun 10th 2009, 10:53 AMAlderDragonPolynomial Long Division
This just confuses me. I am asked to solve these division problems using long division. I know how to do them normally, but long division confuses me.

$\displaystyle \frac{x^3+2x^2+3x-6}{x-1}$

and

$\displaystyle \frac{n^3-27}{n-3}$

Any ideas? - Jun 10th 2009, 11:11 AMAmer
first look at the first term in each divided and the divisor to see what is the number we multiply it with divided to give us the divisor then change the signs(or find the subtraction of them ) then find the sum like this

Attachment 11851

it is clear or not - Jun 10th 2009, 11:27 AMAlderDragon
- Jun 10th 2009, 11:31 AMmasters
Hi AlderDragon,

$\displaystyle \frac{n^3-27}{n-3}=$

Use zeros to hold the places for the terms that are left out.

Code:`n^2 + 3n + 9`

______________________

n - 3 | n^3 + 0n^2 + 0n - 27

(-) n^3 - 3n^2

------------

3n^2 + 0n

(-) 3n^2 - 9n

----------

9n - 27

(-) 9n - 27

========

- Jun 10th 2009, 11:52 AMAmer
Typo sorry