Elimination method in non-linear equation

**galanm** · June 10th 2009, 06:26 AM

x^2 + y^2 = 25 and
x^2 + 7y = 37

**Amer** · June 10th 2009, 06:28 AM

Originally Posted by galanm

x^2 + y^2 = 25 and
x^2 + 7y = 37

multiply one of the equation with -1 and add it to the other one

**mr fantastic** · June 10th 2009, 06:29 AM

Originally Posted by galanm

x^2 + y^2 = 25 and
x^2 + 7y = 37

Substitute x^2 = 37 - 7y from the second equation into the first equation and solve the quadratic equation for y.

**galanm** · June 10th 2009, 06:31 AM

The instructions state to use the elimintation method.

**Amer** · June 10th 2009, 06:36 AM

Originally Posted by galanm

The instructions state to use the elimintation method.

multiply the second one with -1 you will have

$-x^2-7y=-37$

find the sum of that and this

$x^2+y^2=25$

$-x^2-7y+x^2+y^2=27-37$

$y^2-7y+10=0$

$(y-2)(y-5)=0$

$y-2=0...y=2 , y-5=0...y=5$

sub these values of y in one of the equation $x^2+7y=37$ or $x^2+y^2=25$ you will have the values of x this is elimination you eliminate x ...

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