# single fraction

• Jun 10th 2009, 01:06 AM
joey1
single fraction

express as a single fraction (1/x)-(2/x-2)+(x-1/x^2+1)

and (x+1/x^2+1)+(1/x+1)-(1/(x-1)^2)+(2/x-2)

• Jun 10th 2009, 01:22 AM
furor celtica
just put everything to the same denominator then simplify, factorise and cut out the redundant values.
• Jun 10th 2009, 01:59 AM
craig
Quote:

Originally Posted by joey1

express as a single fraction (1/x)-(2/x-2)+(x-1/x^2+1)

and (x+1/x^2+1)+(1/x+1)-(1/(x-1)^2)+(2/x-2)

As furor celtica said you need to make everything have the same denominator, which for your question would be:

$\displaystyle \frac{A}{x(x-2)(x^2+1)}$

For the numerator you need to multiply each term by the other 2 denominator, for example:

$\displaystyle \frac{1(x-2)(x^2+1)...}{x(x-2)(x^2+1)}$.

Repeat this method for your other question.

Hope this helps
• Jun 10th 2009, 02:04 AM
joey1
thanx guys
• Jun 10th 2009, 02:26 AM
joey1
okay guys plese could you confirm my answers
1.x-5x^2-2/x(x-2)(x^2+1)
2.x^3-x^2+2x/x^2-1