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Math Help - surds

  1. #1
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    surds

    1/(1+ sq root 3) - sqroot3/2sqroot3 = asqroot3 +b/ 3 [solve for a

    and b]
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  2. #2
    MHF Contributor
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    Quote Originally Posted by amath9 View Post
    1/(1+ sq root 3) - sqroot3/2sqroot3 = asqroot3 +b/ 3 [solve for a

    and b]

    \frac{1}{1+\sqrt{3}}-\frac{\sqrt{3}}{2\sqrt{3}}=a\sqrt{3}+\frac{b}{3}

    \frac{1}{1+\sqrt{3}}-\frac{1}{2}=a\sqrt{3}+\frac{b}{3}

    -\frac{1-\sqrt{3}}{2}-\frac{1}{2}=a\sqrt{3}+\frac{b}{3}

    \sqrt{3}-2=2a\sqrt{3}+\frac{2b}{3}

    a=1/2 and b=-3
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