I need help solving for x. i am pretty new at this, and not too sure what the first couple steps would be.
log6 X + log6 (X-5)=2
Convert the R.H.S. to logarithmic form in base 6. $\displaystyle (c=b^a\rightarrow a=log_{b}c)$
Use addition formula. $\displaystyle (log_{b}K+log_{b}L=log_b{KL})$
Drop logs.
Have fun solving, because it's all about having fun.
In action.
log6 X + log6 (X-5)=2
log6 X + log6 (X-5)=log6 36
log6 (X(X-5))=log6 36
$\displaystyle X^2-5X=36$
Have fun solving.