I need help solving for x. i am pretty new at this, and not too sure what the first couple steps would be.

log6 X + log6 (X-5)=2

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- Jun 8th 2009, 06:23 PMextraordinarymachinesolving logarithmic equations
I need help solving for x. i am pretty new at this, and not too sure what the first couple steps would be.

log6 X + log6 (X-5)=2 - Jun 8th 2009, 06:32 PMVonNemo19
- Jun 8th 2009, 06:40 PMI-Think
Convert the R.H.S. to logarithmic form in base 6. $\displaystyle (c=b^a\rightarrow a=log_{b}c)$

Use addition formula. $\displaystyle (log_{b}K+log_{b}L=log_b{KL})$

Drop logs.

Have fun solving, because it's all about having fun.

In action.

log6 X + log6 (X-5)=2

log6 X + log6 (X-5)=log6 36

log6 (X(X-5))=log6 36

$\displaystyle X^2-5X=36$

Have fun solving. - Jun 8th 2009, 06:56 PMmr fantastic
- Jun 8th 2009, 07:00 PMextraordinarymachine
Thanks for all your help everyone. i think i understand now. at least to do these types of questions ha ha.