I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?
Thanks in advance!
the Area of triangle is given by
$\displaystyle Area=\left({\color{red}\frac{1}{3}}\right)(base)(h eight)$ you have to thing you know the value of them and one variable right
height = 12
Area=108 the rest for you
I mistake in the Area
$\displaystyle Area=\frac{1}{2}(base)(height)$
$\displaystyle {\underbrace{\overbrace{Thanks- For VonNemo19}}}$
Amer Amer Amer 1/3?
I won't say anything else. YOU'RE BETTER THAN THAT!
$\displaystyle Area=\frac{1}{2}*b*h$
therefore with a little algebra we divide both sides by h
$\displaystyle \frac{A}{h}=\frac{1}{2}*b$
then multiply both sides by 2
$\displaystyle 2*\frac{A}{h}=b$
So the base of ANY triangle is two times the area divided by the hieght.
What's your area and hieght again...............?