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Math Help - length of triangle

  1. #1
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    length of triangle

    I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?
    Thanks in advance!
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  2. #2
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by bookbaby84 View Post
    I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?
    Thanks in advance!

    the Area of triangle is given by

    Area=\left({\color{red}\frac{1}{3}}\right)(base)(h  eight) you have to thing you know the value of them and one variable right

    height = 12
    Area=108 the rest for you

    I mistake in the Area

    Area=\frac{1}{2}(base)(height)

    {\underbrace{\overbrace{Thanks- For VonNemo19}}}
    Last edited by Amer; June 8th 2009 at 09:08 PM.
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  3. #3
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by Amer View Post
    the Area of triangle is given by

    Area=\left(\frac{1}{3}\right)(base)(height) you have to thing you know the value of them and one variable right

    height = 12
    Area=108 the rest for you
    Amer Amer Amer 1/3?

    I won't say anything else. YOU'RE BETTER THAN THAT!

    Area=\frac{1}{2}*b*h

    therefore with a little algebra we divide both sides by h

    \frac{A}{h}=\frac{1}{2}*b

    then multiply both sides by 2

    2*\frac{A}{h}=b

    So the base of ANY triangle is two times the area divided by the hieght.

    What's your area and hieght again...............?
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