# length of triangle

• Jun 8th 2009, 05:41 PM
bookbaby84
length of triangle
I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?
• Jun 8th 2009, 08:24 PM
Amer
Quote:

Originally Posted by bookbaby84
I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?

the Area of triangle is given by

$\displaystyle Area=\left({\color{red}\frac{1}{3}}\right)(base)(h eight)$ you have to thing you know the value of them and one variable right

height = 12
Area=108 the rest for you

I mistake in the Area

$\displaystyle Area=\frac{1}{2}(base)(height)$

$\displaystyle {\underbrace{\overbrace{Thanks- For VonNemo19}}}$
• Jun 8th 2009, 08:33 PM
VonNemo19
Quote:

Originally Posted by Amer
the Area of triangle is given by

$\displaystyle Area=\left(\frac{1}{3}\right)(base)(height)$ you have to thing you know the value of them and one variable right

height = 12
Area=108 the rest for you

Amer Amer Amer (Giggle) 1/3?

(Lipssealed)I won't say anything else. YOU'RE BETTER THAN THAT!

$\displaystyle Area=\frac{1}{2}*b*h$

therefore with a little algebra we divide both sides by h

$\displaystyle \frac{A}{h}=\frac{1}{2}*b$

then multiply both sides by 2

$\displaystyle 2*\frac{A}{h}=b$

So the base of ANY triangle is two times the area divided by the hieght.

What's your area and hieght again...............?