I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?

Thanks in advance!(Nod)

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- Jun 8th 2009, 05:41 PMbookbaby84length of triangle
I have the height (12cm) and area (108cm squared) of a triagle, from these how do I work out the length of its base? Is it as simple as tripling the height? Some how that doesn't seem right?

Thanks in advance!(Nod) - Jun 8th 2009, 08:24 PMAmer

the Area of triangle is given by

$\displaystyle Area=\left({\color{red}\frac{1}{3}}\right)(base)(h eight)$ you have to thing you know the value of them and one variable right

height = 12

Area=108 the rest for you

I mistake in the Area

$\displaystyle Area=\frac{1}{2}(base)(height)$

$\displaystyle {\underbrace{\overbrace{Thanks- For VonNemo19}}}$ - Jun 8th 2009, 08:33 PMVonNemo19
Amer Amer Amer (Giggle) 1/3?

(Lipssealed)I won't say anything else. YOU'RE BETTER THAN THAT!

$\displaystyle Area=\frac{1}{2}*b*h$

therefore with a little algebra we divide both sides by h

$\displaystyle \frac{A}{h}=\frac{1}{2}*b$

then multiply both sides by 2

$\displaystyle 2*\frac{A}{h}=b$

So the base of ANY triangle is two times the area divided by the hieght.

What's your area and hieght again...............?