given that $\displaystyle 32\sqrt{2} = 2^a $ find the value of a. is it correct to say that a = 11/2 so $\displaystyle 2^{\frac{11}{2}} $ = $\displaystyle 32\sqrt{2} $ ?
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$\displaystyle 32\sqrt{2} = 2^5 2^{1/2} = 2^{11/2}$ Yep. 01
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