# surd help

• Jun 6th 2009, 05:49 AM
Tweety
surd help
Quote:

given that $32\sqrt{2} = 2^a$

find the value of a.
is it correct to say that a = 11/2

so $2^{\frac{11}{2}}$ = $32\sqrt{2}$ ?
• Jun 6th 2009, 05:53 AM
yeongil
$32\sqrt{2} = 2^5 2^{1/2} = 2^{11/2}$

Yep.

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