is it correct to say that a = 11/2Quote:

given that $\displaystyle 32\sqrt{2} = 2^a $

find the value of a.

so $\displaystyle 2^{\frac{11}{2}} $ = $\displaystyle 32\sqrt{2} $ ?

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- Jun 6th 2009, 04:49 AMTweetysurd helpQuote:

given that $\displaystyle 32\sqrt{2} = 2^a $

find the value of a.

so $\displaystyle 2^{\frac{11}{2}} $ = $\displaystyle 32\sqrt{2} $ ? - Jun 6th 2009, 04:53 AMyeongil
$\displaystyle 32\sqrt{2} = 2^5 2^{1/2} = 2^{11/2}$

Yep.

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