This is hard to visualize because quarters is 25 cents and dimes is 10 cents. I can't figure this out. Please help.
A student has $6.80 in dimes and quarters. The number of dimes is two more than half the number of quarters. How many of each type of coin does the student have?
Answer key: 22 quarters, 13 dimes
Thanks.
Hello, shenton!
If you're familiar with Systems of Equations, here's another approach.
A student has $6.80 in dimes and quarters.
The number of dimes is two more than half the number of quarters.
How many of each type of coin does the student have?
Answer key: 22 quarters, 13 dimes
Let:
The dimes are worth 10¢ each.
. . Their value is: cents.
The quarters are worth 25¢ each.
. . Their value is: cents.
The total value of the coins is: . (cents) [1]
. . . . . .
We have: . [2]
Divide [1] by 5: .
. . Subtract [2]: .
And we have: .
Substitute into [2]: .
Therefore, there are quarters and dimes.