every 5 minute increment on the face of an analog clock is radians.

let the 3 o'clock position be the zero position for both hands.

at t = 0 (5:15) the minute hand is at and is moving with speed radians per hr.

at t = 0, the hour hand is at radians, moving at radians per hr.

for t in hours, the two hands coincide when their respective positions are the same, ...

hrs

hrs = 12 min + 16.363636... sec

the hands coincide at 5:27 + 16 and sec