1. ## Rearranging

Hello,

Why does $2p-(12-p)=(4p-5)-2p$ have a value of $p=7$. I keep rearranging it incorrectly to get p as -17.

Thanks,
Phil

2. Hi.

Originally Posted by Envy
Hello,

Why does $2p-(12-p)=(4p-5)-2p$ have a value of $p=7$. I keep rearranging it incorrectly to get p as -17.

Thanks,
Phil
2p-(12-p)=(4p-5)-2p

2p - 12 - (-p) = 4p -5 -2p

2p - 12 +p = 4p -5 -2p

2p + p -12 = 4p -2p -5

3p - 12 = 2p - 5

3p - 2p - 12 = -5

1p = 7

p = 7

Yours,
Rapha

3. Originally Posted by Envy
...I keep rearranging it incorrectly to get p as -17.
For future reference, please keep in mind that it is much easier to help you find your errors if we can see what you'd tried. Thank you!