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Math Help - Rearranging

  1. #1
    Newbie
    Joined
    Jun 2009
    Posts
    12

    Rearranging

    Hello,

    Why does 2p-(12-p)=(4p-5)-2p have a value of p=7. I keep rearranging it incorrectly to get p as -17.

    Thanks,
    Phil
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  2. #2
    Senior Member
    Joined
    Nov 2008
    Posts
    461
    Hi.

    Quote Originally Posted by Envy View Post
    Hello,

    Why does 2p-(12-p)=(4p-5)-2p have a value of p=7. I keep rearranging it incorrectly to get p as -17.

    Thanks,
    Phil
    2p-(12-p)=(4p-5)-2p

    2p - 12 - (-p) = 4p -5 -2p

    2p - 12 +p = 4p -5 -2p

    2p + p -12 = 4p -2p -5

    3p - 12 = 2p - 5

    3p - 2p - 12 = -5

    1p = 7

    p = 7

    Yours,
    Rapha
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  3. #3
    MHF Contributor
    Joined
    Mar 2007
    Posts
    1,240

    Talking

    Quote Originally Posted by Envy View Post
    ...I keep rearranging it incorrectly to get p as -17.
    For future reference, please keep in mind that it is much easier to help you find your errors if we can see what you'd tried. Thank you!
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