Hello, Why does $\displaystyle 2p-(12-p)=(4p-5)-2p$ have a value of $\displaystyle p=7$. I keep rearranging it incorrectly to get p as -17. Thanks, Phil
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Hi. Originally Posted by Envy Hello, Why does $\displaystyle 2p-(12-p)=(4p-5)-2p$ have a value of $\displaystyle p=7$. I keep rearranging it incorrectly to get p as -17. Thanks, Phil 2p-(12-p)=(4p-5)-2p 2p - 12 - (-p) = 4p -5 -2p 2p - 12 +p = 4p -5 -2p 2p + p -12 = 4p -2p -5 3p - 12 = 2p - 5 3p - 2p - 12 = -5 1p = 7 p = 7 Yours, Rapha
Originally Posted by Envy ...I keep rearranging it incorrectly to get p as -17. For future reference, please keep in mind that it is much easier to help you find your errors if we can see what you'd tried. Thank you!
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