Hello,

Why does $\displaystyle 2p-(12-p)=(4p-5)-2p$ have a value of $\displaystyle p=7$. I keep rearranging it incorrectly to get p as -17.

Thanks,

Phil

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- Jun 4th 2009, 10:34 AMEnvyRearranging
Hello,

Why does $\displaystyle 2p-(12-p)=(4p-5)-2p$ have a value of $\displaystyle p=7$. I keep rearranging it incorrectly to get p as -17.

Thanks,

Phil - Jun 4th 2009, 11:13 AMRapha
- Jun 6th 2009, 04:52 AMstapel