Trying to help my little brother through this particular problem but im stumped. In the book it says the correct answer is $\displaystyle \frac{4x}{9} $, ive gone through all the rest of his example problems but have been able to solve them successfully.

$\displaystyle \frac{10}{3}*\frac{2x}{15}$

LCD

15

$\displaystyle \frac{10}{3}*\frac{5}{5} * \frac{2x}{15}*\frac{1}{1} = \frac{50+2x}{15}$

Thanks