# Basic Fraction Algebra

• Jun 3rd 2009, 05:33 PM
cmf0106
Basic Fraction Algebra
Trying to help my little brother through this particular problem but im stumped. In the book it says the correct answer is $\displaystyle \frac{4x}{9}$, ive gone through all the rest of his example problems but have been able to solve them successfully.

$\displaystyle \frac{10}{3}*\frac{2x}{15}$

LCD
15

$\displaystyle \frac{10}{3}*\frac{5}{5} * \frac{2x}{15}*\frac{1}{1} = \frac{50+2x}{15}$

Thanks
• Jun 3rd 2009, 05:45 PM
Sodapop
10 * 2x = 20x
3 * 15 = 45

When facing a multiplication of two fractions, you can simply multiply both numerators together and both denominators together. You'll end up having one fraction, that you can eventually simplify. :)

20x/45 = 4x/9
• Jun 3rd 2009, 05:47 PM
cmf0106
Quote:

Originally Posted by Sodapop
10 * 2x = 20x
3 * 15 = 45

When facing a multiplication of two fractions, you can simply multiply both numerators and both denominators togheter. You'll end up having one fraction, that you can eventually simplify. :)

20x/45 = 4x/9

Thanks! And I cant believe I glossed over that. I suppose thats what happens when you get off a double shift.
• Jun 3rd 2009, 05:48 PM
Sodapop
Quote:

Originally Posted by cmf0106
Thanks! And I cant believe I glossed over that. I suppose thats what happens when you get off a double shift.

As I always said, simple things can sometimes be harder than the tough ones. And I have proven this, with life experiments. :p