could you please help me solve this equation
$\displaystyle x-4y=-2$
$\displaystyle y=2x-3$
Substitute the value of y into the first equation.
$\displaystyle x - 4(2x - 3) = -2$
$\displaystyle x - 8x + 12 = -2$
$\displaystyle -7x + 12 = -2$
$\displaystyle -7x = -14$
$\displaystyle x = 2$.
Back substitute to find y.
$\displaystyle y = 2x - 3$
$\displaystyle y = 2\times 2 - 3$
$\displaystyle y = 4 - 3$
$\displaystyle y = 1$.