1. How to simplify this answer?

How to simplify this my answer to 2x+2y-13=0

$\frac{4x-2y-15}{2\sqrt{5}}$= $\frac{2x-y-1}{\sqrt{5}}$

How to simplify my answer to get 2x+2y-13=0

Thank you

2. =

Hmm... It looks like you tried to factor a 2 out of the numerator and then cancel 2 from both the numerator and denominator but..

Factor 2 out of -15 and get... -1?

I'm not sure what your original problem was, but you may want to re-check your arithmetic over all.

3. Can you post the original problem?

01

4. Originally Posted by mj.alawami
How to simplify this my answer to 2x+2y-13=0

$\frac{4x-2y-15}{2\sqrt{5}}$= $\frac{2x-y-1}{\sqrt{5}}$

How to simplify my answer to get 2x+2y-13=0

Thank you

$\frac{4x-2y-15}{2\sqrt{5}}$= $\frac{2x-y-1}{\sqrt{5}}$

multiplying both sides by $2\sqrt{5}$ Yields

$4x-2y-15=2(2x-y-1)\Longleftrightarrow{4x-2y-15}=4x-2y-2\Longleftrightarrow-15=-2$??

It appears that something has gone way way wrong here. The only way to simplify your answer to the given equation would be to develop a new branch of Mathematics

Sorry buddy. but if you post the original problem, I'm here for you.

5. Hello, mj.alawami!

My answer is: . $\frac{4x-2y-15}{2\sqrt{5}} \:=\: \frac{2x-y-1}{\sqrt{5}}$ . . . . wrong!

How to simplify my answer to get: . $2x+2y-13\:=\:0$

You have: . $\frac{4x-2y - 15}{2\sqrt{5}} \;=\;\frac{2x-y-1}{\sqrt{5}}$

Multiply by $2\sqrt{5}\!:\quad 4x - 2y - 15 \;=\;2(2x-y-1) \quad\Rightarrow\quad 4x - 2y - 15 \:=\:4x - 2y - 2$

. . and we have: . $-15 \:=\:-2 \quad\Rightarrow\quad 0 \:=\:13 \;\;??$

I believe you need to have: . $\frac{4x-2y - 15}{2\sqrt{5}} \;=\;\frac{{\color{red}x - 2y} - 1}{\sqrt{5}}$