How to simplify this my answer to 2x+2y-13=0
My answer is :-
$\displaystyle \frac{4x-2y-15}{2\sqrt{5}} $= $\displaystyle \frac{2x-y-1}{\sqrt{5}} $
How to simplify my answer to get 2x+2y-13=0
Thank you
$\displaystyle \frac{4x-2y-15}{2\sqrt{5}} $= $\displaystyle \frac{2x-y-1}{\sqrt{5}} $
multiplying both sides by $\displaystyle 2\sqrt{5}$ Yields
$\displaystyle 4x-2y-15=2(2x-y-1)\Longleftrightarrow{4x-2y-15}=4x-2y-2\Longleftrightarrow-15=-2$??
The logic has gone bad.............
It appears that something has gone way way wrong here. The only way to simplify your answer to the given equation would be to develop a new branch of Mathematics
Sorry buddy. but if you post the original problem, I'm here for you.
Hello, mj.alawami!
You made an error somewhere.
Your answer is quite impossible.
My answer is: .$\displaystyle \frac{4x-2y-15}{2\sqrt{5}} \:=\: \frac{2x-y-1}{\sqrt{5}} $ . . . . wrong!
How to simplify my answer to get: .$\displaystyle 2x+2y-13\:=\:0$
You have: .$\displaystyle \frac{4x-2y - 15}{2\sqrt{5}} \;=\;\frac{2x-y-1}{\sqrt{5}} $
Multiply by $\displaystyle 2\sqrt{5}\!:\quad 4x - 2y - 15 \;=\;2(2x-y-1) \quad\Rightarrow\quad 4x - 2y - 15 \:=\:4x - 2y - 2$
. . and we have: .$\displaystyle -15 \:=\:-2 \quad\Rightarrow\quad 0 \:=\:13 \;\;??$
I believe you need to have: .$\displaystyle \frac{4x-2y - 15}{2\sqrt{5}} \;=\;\frac{{\color{red}x - 2y} - 1}{\sqrt{5}} $