The perimeter of a rectangle is 76 inches. The length of the rectangle is 5 more than twice its width. Which equation can be used to find the width? a. w+(2w+5)=76 b. 2[w(2w+5]=76 c. w(2w+5)=76 d. 2[w+(2w+5)]=76
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Originally Posted by tiffieblah The perimeter of a rectangle is 76 inches. The length of the rectangle is 5 more than twice its width. Which equation can be used to find the width? a. w+(2w+5)=76 b. 2[w(2w+5]=76 c. w(2w+5)=76 d. 2[w+(2w+5)]=76 d. Because the width is w, and length is 2w+5 (5 more than twice the width), and since p=2(w+l), we have 2[w+(2w+5)]=76.
Last edited by VonNemo19; May 31st 2009 at 07:04 PM.
tnx u mwah
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