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Math Help - Another rectangle problem

  1. #1
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    Another rectangle problem

    The perimeter of a rectangle is 76 inches. The length of the rectangle is 5 more than twice its width. Which equation can be used to find the width?

    a. w+(2w+5)=76
    b. 2[w(2w+5]=76
    c. w(2w+5)=76
    d. 2[w+(2w+5)]=76

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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by tiffieblah View Post
    The perimeter of a rectangle is 76 inches. The length of the rectangle is 5 more than twice its width. Which equation can be used to find the width?

    a. w+(2w+5)=76
    b. 2[w(2w+5]=76
    c. w(2w+5)=76
    d. 2[w+(2w+5)]=76

    d. Because the width is w, and length is 2w+5 (5 more than twice the width), and since p=2(w+l), we have 2[w+(2w+5)]=76.
    Last edited by VonNemo19; May 31st 2009 at 07:04 PM.
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  3. #3
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    tnx u mwah
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