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Math Help - Rectangle problem??

  1. #1
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    Rectangle problem??

    I have never known how to do these problems and there are plenty on the exam.


    A rectangle has an area of (x^3-6x^2+10x-8) square meters and a width of (x-4) meters. What is its length?

    How would I set this problem up???
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  2. #2
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    Quote Originally Posted by tiffieblah View Post
    I have never known how to do these problems and there are plenty on the exam.


    A rectangle has an area of (x^3-6x^2+10x-8) square meters and a width of (x-4) meters. What is its length?

    How would I set this problem up???
    If we just forget about the x for a minute, I'm sure you know that the equation for the area of a rectangle is A = w \times l

    Putting your above values into that question, we get the equation:

    x^3-6x^2+10x-8 = (x - 4)l

    Or l = \frac{x^3-6x^2+10x-8}{x - 4}

    What we have now is just a simple polynomial division question.

    There are several methods to solve this, I would suggest Synthetic Division, but use whatever method you have been taught.

    Hope this helps
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  3. #3
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    yay yay yay yay yay!!!!!!!!!!!!!!!!!!
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