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Math Help - Solve for Variable

  1. #1
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    Solve for Variable

    S= n/2[2a + (n - 1)d]

    please solve and show the steps to get there. I'm confused at how they reached the answer the book has. Thanks
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  2. #2
    Member pberardi's Avatar
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    Quote Originally Posted by suddenlysmarter View Post
    S= n/2[2a + (n - 1)d]

    please solve and show the steps to get there. I'm confused at how they reached the answer the book has. Thanks
    For which variable do you need to solve for?
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  3. #3
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    Quote Originally Posted by suddenlysmarter View Post
    S= n/2[2a + (n - 1)d]

    please solve and show the steps to get there. I'm confused at how they reached the answer the book has. Thanks
    This is the formula for the sum of the first n terms of an arithmetic series. I suggest you consult your textbook or class notes for the derivation (or Google it).

    If you're attempting to apply this formula in a specific question, it would help if you actually posted that question. We are not mind readers.
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  4. #4
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    Sorry it was solve for a

    Sorry it was solve for a and I just can't see to figure out how they achieved the answer they got. How would you approach this. In order for me to understand I would need to see how you reached your answer.

    Anyone who is up for the challenge. I would greatly appreciate it.
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  5. #5
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    S = n/2[2a + (n - 1)d]

    2S/n = 2a + nd - d

    2S/n - nd + d = 2a

    S/n - (1/2)nd + (1/2)d = a
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  6. #6
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    S= n/2[2a + (n - 1)d]

    2S/n = 2a + nd - d

    2S/n - nd + d = 2a

    S/n - (1/2)nd + (1/2)d = a
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  7. #7
    Member pberardi's Avatar
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    Quote Originally Posted by suddenlysmarter View Post
    Sorry it was solve for a and I just can't see to figure out how they achieved the answer they got. How would you approach this. In order for me to understand I would need to see how you reached your answer.

    Anyone who is up for the challenge. I would greatly appreciate it.
    S = n/2[2a+(n-1)d] Solve for a
    First multiply by 2
    2S = n[2a +(n-1)d]
    Divide by n
    2S/n = 2a + (n-1)d
    Subtract the term (n-1)d
    2S/n -(n-1)d = 2a
    Divide by 2
    S/n -(n-1)d/2 = a

    Simplify as you wish. Helps?
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