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Math Help - Scientific Equation - Solve for Variable

  1. #1
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    Scientific Equation - Solve for Variable

    Please can someone explain how this answer was achieved?

    Solve for C

    S=C+RC

    The answer they have is:

    C= 5
    -------
    1 + R
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  2. #2
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    Scientific Equation - Solving for a variable.

    Here's the question:

    Solve for b.

    A= 1 * (a + b)h
    _
    2

    Just for clarity that is 1 over 2 (as in a half, I don't know how to make it look like it does on my page using my computer keyboard).

    The answer they gave is:

    2A - ah
    --------
    h

    I got...

    2A - a
    --------
    h

    I'm confused about how the h ended up on the top and the bottom of the equation when you would be simply multiplying by 1 over h or should you be working out the expression so that is becomes ah + bh first?
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  3. #3
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    Quote Originally Posted by suddenlysmarter View Post
    Please can someone explain how this answer was achieved?

    Solve for C

    S=C+RC

    The answer they have is:

    C= 5 .........<<<<<< this should be S
    -------
    1 + R
    <br />
\begin{aligned}S&= C + RC \\<br />
S&=C(1+R)\\\dfrac{S}{1+R}&=C\end{aligned}
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  4. #4
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    Quote Originally Posted by suddenlysmarter View Post
    Here's the question:

    Solve for b.

    A= 1 * (a + b)h
    _
    2

    Just for clarity that is 1 over 2 (as in a half, I don't know how to make it look like it does on my page using my computer keyboard).

    The answer they gave is:

    2A - ah
    --------
    h

    I got...

    2A - a
    --------
    h

    I'm confused about how the h ended up on the top and the bottom of the equation when you would be simply multiplying by 1 over h or should you be working out the expression so that is becomes ah + bh first?
    \begin{aligned}A&=\dfrac12 (a+b)h\\<br />
\dfrac{2A}h&=a+b \\<br />
\dfrac{2A}h - a &=b \\<br />
\dfrac{2A}h - \dfrac{ah}h &=b \\<br />
\dfrac{2A-ah}h  &=b \end{aligned}
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