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Math Help - Differentiation

  1. #1
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    Differentiation

    Following formula shows the veloctiy, vms-1, at time t seconds for the first 8 seconds of motion:

    v=(60t^2-5t^3)/64

    Find the acceleration when t=8

    I know you have to differentiate and i got 120t-15t^2
    However, the mark scheme says to reduce the mark if 64 is left off - why would you leave 64 on?

    Equally when I intergrate the formula, apparently 64 is not 64t but just 64, why?

    Thanks Very Much
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  2. #2
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    Quote Originally Posted by p4pri View Post
    Following formula shows the veloctiy, vms-1, at time t seconds for the first 8 seconds of motion:

    v=(60t^2-5t^3)/64

    Find the acceleration when t=8

    I know you have to differentiate and i got 120t-15t^2
    However, the mark scheme says to reduce the mark if 64 is left off - why would you leave 64 on?

    Equally when I intergrate the formula, apparently 64 is not 64t but just 64, why?

    Thanks Very Much
    because of the constant multiple rule ...

    \frac{d}{dt}[k \cdot f(t)] = k \cdot f'(t)

    think of k as \frac{1}{64}
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