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Thread: [SOLVED] Addition of Algeraic Fractions

  1. #1
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    [SOLVED] Addition of Algeraic Fractions

    Q. Simplify:$\displaystyle \frac {m}{m^2 + mn} + \frac {n}{n^2 + mn}$

    this is the furthest i've gotten, im not sure if its even right so far

    $\displaystyle \frac {2mn}{m + n( m + n)}$

    Thanks
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  2. #2
    MHF Contributor alexmahone's Avatar
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    $\displaystyle \frac{m}{m^2+mn}+\frac{n}{n^2+mn}$
    =$\displaystyle \frac{1}{m+n}+\frac{1}{n+m}$
    =$\displaystyle \frac{2}{m+n}$
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  3. #3
    Newbie findmehere.genius's Avatar
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    sure I too got to same result:

    $\displaystyle 2/(m+n)$
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  4. #4
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    Quote Originally Posted by waven View Post
    Q. Simplify:$\displaystyle \frac {m}{m^2 + mn} + \frac {n}{n^2 + mn}$

    this is the furthest i've gotten, im not sure if its even right so far

    $\displaystyle \frac {2mn}{m + n( m + n)}$

    Thanks
    so you can cancel the m's in the first fraction to get
    1/m+n

    and cancel the n's in the second fraction to get

    1/n+m

    now you can add them to get
    (1/m+n) + (1/n+m)
    =
    2/m+n
    ass the denominators are the samm
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