# [SOLVED] Addition of Algeraic Fractions

• May 26th 2009, 06:59 PM
waven
Q. Simplify:$\displaystyle \frac {m}{m^2 + mn} + \frac {n}{n^2 + mn}$

this is the furthest i've gotten, im not sure if its even right so far

$\displaystyle \frac {2mn}{m + n( m + n)}$

Thanks
• May 26th 2009, 07:13 PM
alexmahone
$\displaystyle \frac{m}{m^2+mn}+\frac{n}{n^2+mn}$
=$\displaystyle \frac{1}{m+n}+\frac{1}{n+m}$
=$\displaystyle \frac{2}{m+n}$
• May 26th 2009, 09:47 PM
findmehere.genius
sure I too got to same result:

$\displaystyle 2/(m+n)$
• May 27th 2009, 02:13 PM
scoobydoo4
Quote:

Originally Posted by waven
Q. Simplify:$\displaystyle \frac {m}{m^2 + mn} + \frac {n}{n^2 + mn}$

this is the furthest i've gotten, im not sure if its even right so far

$\displaystyle \frac {2mn}{m + n( m + n)}$

Thanks

so you can cancel the m's in the first fraction to get
1/m+n

and cancel the n's in the second fraction to get

1/n+m

now you can add them to get
(1/m+n) + (1/n+m)
=
2/m+n
ass the denominators are the samm