√x2 + 1 + √x2 – 2x + 3 = 3

│ x-4 │ - │ 2–0,5x│ ≤ 3

│5- x2-6 │= x2-5x-6

x2-2x+3 : x2-4x+3 > -2

I'm so fail at math soo..would someone please help me ? :)

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- May 25th 2009, 07:52 PMfreakofsomethingelseNeed help with few exercises. Please help!
√x2 + 1 + √x2 – 2x + 3 = 3

│ x-4 │ - │ 2–0,5x│ ≤ 3

│5- x2-6 │= x2-5x-6

x2-2x+3 : x2-4x+3 > -2

I'm so fail at math soo..would someone please help me ? :)

- May 26th 2009, 01:10 AMShowcase_22
For the first one, do you mean $\displaystyle \sqrt{x^2}$?

Quote:

│ x-4 │ - │ 2–0,5x│ ≤ 3

$\displaystyle x-4-(2-0.5x) \leq 3$

$\displaystyle 4-x-(2-0.5x) \leq 3$

$\displaystyle x-4-(0.5x-2) \leq 3$

$\displaystyle 4-x-(0.5x-2) \leq 3$

The other one can be done in a similar way.