Thread: Question of complex power & cube roots

Hi everyone,

3+4i^(3/2) =
z = 3 + 41
z = 5(cos 0.9273 + isin0.9273 )
z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 )

Is it correct? Pls advise,just wanted to confirm.

Thank you & regards

Originally Posted by anderson

Hi everyone,

3+4i^(3/2) =
z = 3 + 41
z = 5(cos 0.9273 + isin0.9273 )
z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 )

Is it correct? Pls advise,just wanted to confirm.

Thank you & regards

Try explaining what you are asking for and what you have done.

(and guessing what you are trying to do, no it does not look right)

CB

Originally Posted by anderson

Hi everyone,

3+4i^(3/2) =
z = 3 + 41
z = 5(cos 0.9273 + isin0.9273 )
z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 )

You don't mean that last "=" do you? And you should be multiplying by "3" not "2".

Is it correct? Pls advise,just wanted to confirm.

Thank you & regards

yup ur right, typo error.

thanks.