Hi everyone, 3+4i^(3/2) = z = 3 + 41 z = 5(cos 0.9273 + isin0.9273 ) z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 ) Is it correct? Pls advise,just wanted to confirm. Thank you & regards
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Originally Posted by anderson Hi everyone, 3+4i^(3/2) = z = 3 + 41 z = 5(cos 0.9273 + isin0.9273 ) z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 ) Is it correct? Pls advise,just wanted to confirm. Thank you & regards Try explaining what you are asking for and what you have done. (and guessing what you are trying to do, no it does not look right) CB
Originally Posted by anderson Hi everyone, 3+4i^(3/2) = z = 3 + 41 z = 5(cos 0.9273 + isin0.9273 ) z^(3/2) = 5^(3/2) = ( cos2((2pik + 0.273))/2 + isin2((2pik + 0.273))/2 ) You don't mean that last "=" do you? And you should be multiplying by "3" not "2". Is it correct? Pls advise,just wanted to confirm. Thank you & regards
yup ur right, typo error. thanks.
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