really good start
You can take out in the bottom of the first term and you can apply the difference of 2 squares in the top of the second term to get.
after cancelling leaves you with
Hmm, i have this problem and i was trying to figure it out, but i didn't know when to stop because i don't have a solution.
here is the problem and then i supplied where i thought i couldn't do anymore, thanks alot.
(x^2 - 2x - 35) / (2x^3 - 3x^2) multiplied by (4x^3 - 9x)/(7x - 49)
...i factored to get:
(x+5)(x-7) / x(2x^2 - 3x) multiplied by ( x(4x^2-9) / ( 7(x-7)
x-7's clearly cancel, not sure about the others, i could cancel some more but then i'm still stuck with some other variables.
I understand the concept, just had no answer to check when to stop the problem.