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Math Help - multiplying polynomials.

  1. #1
    Senior Member
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    multiplying polynomials.

    Hmm, i have this problem and i was trying to figure it out, but i didn't know when to stop because i don't have a solution.

    here is the problem and then i supplied where i thought i couldn't do anymore, thanks alot.

    problem:
    (x^2 - 2x - 35) / (2x^3 - 3x^2) multiplied by (4x^3 - 9x)/(7x - 49)

    ...i factored to get:

    (x+5)(x-7) / x(2x^2 - 3x) multiplied by ( x(4x^2-9) / ( 7(x-7)

    x-7's clearly cancel, not sure about the others, i could cancel some more but then i'm still stuck with some other variables.

    I understand the concept, just had no answer to check when to stop the problem.

    thanks alot.
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  2. #2
    Master Of Puppets
    pickslides's Avatar
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    really good start

    You can take out x^2 in the bottom of the first term and you can apply the difference of 2 squares in the top of the second term to get.

     \frac{(x+5)(x-7)}{x^2(2x-3)}\times \frac{x(2x-3)(2x+3)}{7(x-7)}

    after cancelling leaves you with

     \frac{(x+5)}{x}\times \frac{(2x+3)}{7}

    finally

     \frac{(x+5)(2x+3)}{7x}
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