1. ## multiplying polynomials.

Hmm, i have this problem and i was trying to figure it out, but i didn't know when to stop because i don't have a solution.

here is the problem and then i supplied where i thought i couldn't do anymore, thanks alot.

problem:
(x^2 - 2x - 35) / (2x^3 - 3x^2) multiplied by (4x^3 - 9x)/(7x - 49)

...i factored to get:

(x+5)(x-7) / x(2x^2 - 3x) multiplied by ( x(4x^2-9) / ( 7(x-7)

x-7's clearly cancel, not sure about the others, i could cancel some more but then i'm still stuck with some other variables.

I understand the concept, just had no answer to check when to stop the problem.

thanks alot.

2. really good start

You can take out $x^2$ in the bottom of the first term and you can apply the difference of 2 squares in the top of the second term to get.

$\frac{(x+5)(x-7)}{x^2(2x-3)}\times \frac{x(2x-3)(2x+3)}{7(x-7)}$

after cancelling leaves you with

$\frac{(x+5)}{x}\times \frac{(2x+3)}{7}$

finally

$\frac{(x+5)(2x+3)}{7x}$