Alright, I wanted to check and see if I got my answer right to this following question..
I came up with x over 3x+4
Thanks
Alright, I wanted to check and see if I got my answer right to this following question..
I came up with x over 3x+4
Thanks
$\displaystyle \frac{x^2-16}{x-4} \div \frac{3x+12}{x}$
change divide into times by flipping the second term
$\displaystyle \frac{x^2-16}{x-4} \times \frac{x}{3x+12}$
now factor the top of the first term using difference of 2 squares and the bottom of the second term by taking out a common factor
$\displaystyle \frac{(x-4)(x+4)}{x-4} \times \frac{x}{3(x+4)}$
now times the 2 terms together you get
$\displaystyle \frac{(x-4)(x+4)x}{3(x+4)(x-4)} $
and cancelling out terms
$\displaystyle \frac{x}{3} $