Hello, SportfreundeKeaneKent!
Here are a couple of them . . .
2) Solve: .$\displaystyle (\ln x)^2\:=\:\ln(x^2)$
We have: .$\displaystyle (\ln x)^2\:=\:2\ln x\quad\Rightarrow\quad (\ln x)^2  2\ln x \:=\:0$
Factor: .$\displaystyle \ln x(\ln x  2)\:=\:0$
And we have two equations to solve:
. . $\displaystyle \ln x \,= \,0\quad\Rightarrow\quad\boxed{ x \,= \,1}$
. . $\displaystyle \ln x \,=\,2\quad\Rightarrow\quad\boxed{ x \,= \,e^2}$
3) The graph of $\displaystyle y = \ln x$ is rotated 90° CCW about the origin.
What is the equation of the new graph?
The graph of $\displaystyle y = \ln x$ looks like this: Code:

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+*
 * 1
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*

Rotated 90° CCW, it looks like this: Code:
* 

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*
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+

We're expected to recognize this as the graph of: $\displaystyle y \:=\:e^{x}$