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Math Help - College Algebra Question

  1. #1
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    Arrow College Algebra Question

    I have the answers to this question but as I am looking through my notes I am confused at how my professor got the answers. If someone could explain it to me would really help me out -- Thankyou

    the Problem is x3-36x=16(x-6)

    So far I have :

    x(x2-36)=16(x-6)
    x(x-6)(x+6)=16(x-6)

    and I get confused on what to do next ....
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by Yup318 View Post
    I have the answers to this question but as I am looking through my notes I am confused at how my professor got the answers. If someone could explain it to me would really help me out -- Thankyou

    the Problem is x3-36x=16(x-6)

    So far I have :

    x(x2-36)=16(x-6)
    x(x-6)(x+6)=16(x-6)

    and I get confused on what to do next ....
    Put everything onto one side and factor out (x-6):

    (x-6)([x(x+6)]-16) = 0

    We know that either (x-6) = 0 or x(x+6)-16=0.
    Therefore one solution is x=6

    Expand the other factor to give x^2+6x-16=0

    Then solve using your favourite method.

    I get the roots to be -8, 2 and 6
    Last edited by e^(i*pi); May 21st 2009 at 09:35 AM. Reason: Added in method to find third root
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