I am having some difficulty finding x = 0 for this equation

$\displaystyle \frac{-6x^2-12x}{x^5}=0$

solve for numerator = 0

$\displaystyle -6x^2-12x=0$

then factorize?

$\displaystyle -6x(6x+2)=0$

then for $\displaystyle 6x+2=0, x=\frac{-1}{3}$

and x = 0

I don't know if i'm doing it correct