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Math Help - Another fraction prob

  1. #1
    Junior Member
    Joined
    May 2009
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    Another fraction prob

    I am having some difficulty finding x = 0 for this equation

    \frac{-6x^2-12x}{x^5}=0

    solve for numerator = 0

    -6x^2-12x=0

    then factorize?

    -6x(6x+2)=0

    then for 6x+2=0, x=\frac{-1}{3}

    and x = 0

    I don't know if i'm doing it correct
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  2. #2
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    Should be -6x(x + 2) = 0
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  3. #3
    Member SENTINEL4's Avatar
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    \frac{-6x^2-12x}{x^5}=0 \Rightarrow \frac{-6x(x+2)}{x^5}=0 \Rightarrow
    \frac{-6(x+2)}{x^4}=0

    x can't be 0 so i t would be -6(x+2)=0 \Rightarrow x+2=0 \Rightarrow x=-2
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