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Thread: Another fraction prob

  1. #1
    Junior Member
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    Another fraction prob

    I am having some difficulty finding x = 0 for this equation

    $\displaystyle \frac{-6x^2-12x}{x^5}=0$

    solve for numerator = 0

    $\displaystyle -6x^2-12x=0$

    then factorize?

    $\displaystyle -6x(6x+2)=0$

    then for $\displaystyle 6x+2=0, x=\frac{-1}{3}$

    and x = 0

    I don't know if i'm doing it correct
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  2. #2
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    Should be -6x(x + 2) = 0
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  3. #3
    Member SENTINEL4's Avatar
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    $\displaystyle \frac{-6x^2-12x}{x^5}=0$ $\displaystyle \Rightarrow$ $\displaystyle \frac{-6x(x+2)}{x^5}=0$ $\displaystyle \Rightarrow$
    $\displaystyle \frac{-6(x+2)}{x^4}=0$

    x can't be 0 so i t would be $\displaystyle -6(x+2)=0$ $\displaystyle \Rightarrow$ $\displaystyle x+2=0$ $\displaystyle \Rightarrow$ $\displaystyle x=-2$
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