
Another fraction prob
I am having some difficulty finding x = 0 for this equation
$\displaystyle \frac{6x^212x}{x^5}=0$
solve for numerator = 0
$\displaystyle 6x^212x=0$
then factorize?
$\displaystyle 6x(6x+2)=0$
then for $\displaystyle 6x+2=0, x=\frac{1}{3}$
and x = 0
I don't know if i'm doing it correct :(


$\displaystyle \frac{6x^212x}{x^5}=0$ $\displaystyle \Rightarrow$ $\displaystyle \frac{6x(x+2)}{x^5}=0$ $\displaystyle \Rightarrow$
$\displaystyle \frac{6(x+2)}{x^4}=0$
x can't be 0 so i t would be $\displaystyle 6(x+2)=0$ $\displaystyle \Rightarrow$ $\displaystyle x+2=0$ $\displaystyle \Rightarrow$ $\displaystyle x=2$