Hey!
I need some help with solving this equation for x...
(1+(6^2*x^-2))^-1*(-6x^-2)-(1+(4^2*x^-2))^-1*(-4x^-2) = 0
I have problem with (1+(6^2*x^-2))^-1 and (1+(4^2*x^-2))^-1
thanks
$\displaystyle (1+(6^2x^{-2}))^{-1}(-6x^{-2})-(1+(4^2x^{-2}))^{-1}(-4x^{-2}) = 0$
$\displaystyle x^{-a} = \frac 1{x^a}$
$\displaystyle \frac 1{(1+(6^2x^{-2}))} * \frac{-6}{x^{2}}-\frac 1{(1+(4^2x^{-2}))} * \frac{-4}{x^{2}} = 0$
$\displaystyle \frac {-6}{x^{-2}(1+(6^2x^{-2}))} - \frac{-4}{x^{-2}(1 + (4^2x^{-2}))} = 0$