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Math Help - [SOLVED] Multiplication of Algeraic Fractions

  1. #1
    Junior Member
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    [SOLVED] Multiplication of Algeraic Fractions

    Q. Simplify: \frac {a^2 - b^2 + a - b}{a^2 - 4ab + 3b^2} \times \frac {a^2 - 3ab}{a + b + 1}

    this is the furthest i've gotten, im not sure if its even right so far

    \frac {(a + b)(a - b) + (a - b)}{a^2 - 4ab + 3b^2} \times \frac {a(a - 3b)}{a + b + 1}

    Thanks
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  2. #2
    Newbie Singaporean's Avatar
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    From where you left off
    \frac {(a-b)((a+b)+1)}{(a-3b)(a-b)} \times \frac {a(a-3b)}{a+b+1}

    Proceeding to cancel similar terms,
    \frac {(a-b)}{(a-3b)(a-b)} \times \frac {a(a-3b)}{1}

    \frac {(a-b)}{(a-b)} \times {a}

    {a}

    i think this is the correct ans if i am wrong, i hope this at least help u abit
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  3. #3
    Member SENTINEL4's Avatar
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    I found as a result "a"
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