Hi,

Could you please explain how to solve these two sums, step by step please.

1. $\displaystyle 2x^3=16x$

2. $\displaystyle 2(x-1)^3=32$

This is as far as I got on both sums:

1.

$\displaystyle 2x^3=16x$

$\displaystyle x^3=8x$

$\displaystyle x^2=8$

$\displaystyle x^2-8=0$

2.

$\displaystyle 2(x-1)^3=32$

$\displaystyle (x-1)^3=16$

$\displaystyle (x-1)^3-16=0$

Any help would be greatly appreciated,

Thanks,

Dru