I have an equation that I need to solve for x in which i have no clue of how to solve it
Please Help if you can
0 = 80x(500^2+x^2)^(-1/2) - 50
$\displaystyle \frac{80x}{\sqrt{500^2+x^2}} = 50$
$\displaystyle \frac{8x}{5} = \sqrt{500^2+x^2}$
$\displaystyle \frac{64x^2}{25} = 500^2 + x^2$
$\displaystyle \frac{39x^2}{25} = 500^2$
$\displaystyle 39x^2 = 25 \cdot 500^2$
$\displaystyle x = \pm \sqrt{\frac{25 \cdot 500^2}{39}}$
check both solutions in the original equation