1. ## f(g(x))

For the following question, I was unable to match my answer for f(g(x)).

f(x) = 2x - 3 g(x) = (1/5x)

The steps that I have so far to solve for f(g(x)) are as follows:

f((1/5x)) ---> 2(1/5x) - 3 ----> (2/5x) - 3

But the right answer is (2 - 15x) / 5x.

Would someone be kind enough to step me through this and show where I went wrong? Thanks!

2. Originally Posted by Hapa
For the following question, I was unable to match my answer for f(g(x)).

f(x) = 2x - 3 g(x) = (1/5x)

The steps that I have so far to solve for f(g(x)) are as follows:

f((1/5x)) ---> 2(1/5x) - 3 ----> (2/5x) - 3

But the right answer is (2 - 15x) / 5x.
$\displaystyle \frac{2- 15x}{5x}= \frac{2}{5x}- \frac{15x}{5x}= \frac{2}{5}x- 3$

Those are both the same answer.

Would someone be kind enough to step me through this and show where I went wrong? Thanks!
You didn't go wrong!