An and Bn are two series given by:

An = + + + + …… + (4n–3

Bn = + + + + ….

For n = 1, 2, 3,….

i. Find the nth term of Bn.

Tn =

ii. If Sn = An – Bn, prove that S2n =

i have so far for this only

Sn = + + + + …… + (4n–3

- ( + + + + )

and have absolutely no idea how to proceed from here

iii. Hence, evaluate – + – + …… + -

any help greatly appreciated

thanks