An and Bn are two series given by:
An = + + + + …… + (4n–3
Bn = + + + + ….
For n = 1, 2, 3,….
i. Find the nth term of Bn.
Tn =
ii. If Sn = An – Bn, prove that S2n =
i have so far for this only
Sn = + + + + …… + (4n–3
- ( + + + + )
and have absolutely no idea how to proceed from here
iii. Hence, evaluate – + – + …… + -
any help greatly appreciated
thanks