Can someone please help me with these radicals
√[3/8]
3√[16] rasied dot 3√[3]
Thank you so much
Please note that on the second question the 3's are the indexs
Change this to:
$\displaystyle \frac{\sqrt{3}}{\sqrt{8}}$
Since you want to get rid of the square root in the denominator, multiply the top and bottom by $\displaystyle \sqrt{8}$ giving:
$\displaystyle \frac{\sqrt{3}\sqrt{8}}{8}$
So,
$\displaystyle \frac{\sqrt{24}}{8}$
Then if you need to simplify, you can factor out 3 (since 3 x 3 x 3 = 24) giving you:
$\displaystyle \frac{3\sqrt{3}}{8}$
Not sure what you have here, is it $\displaystyle \sqrt[3]{16}\cdot \sqrt[3]{3}$ ??3√[16] rasied dot 3√[3]
Thank you so much
Please note that on the second question the 3's are the indexs
Well, $\displaystyle \sqrt[3]{16} \cdot \sqrt[3]{3}$ = $\displaystyle \sqrt[3]{48} $
$\displaystyle =\sqrt[3]{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}$
$\displaystyle = 2\sqrt[3]{6}$
If you are supposed to get a non-radical answer, use a calculator. You can calculate a cubed root of a number by raising that number to $\displaystyle \frac{1}{3}$