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Math Help - Need more help with radicals

  1. #1
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    Need more help with radicals

    Can someone please help me with these radicals

    √[3/8]




    3√[16] rasied dot 3√[3]


    Thank you so much

    Please note that on the second question the 3's are the indexs
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  2. #2
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by mr_quick View Post
    Can someone please help me with these radicals

    √[3/8]
    Change this to:

    \frac{\sqrt{3}}{\sqrt{8}}

    Since you want to get rid of the square root in the denominator, multiply the top and bottom by \sqrt{8} giving:

    \frac{\sqrt{3}\sqrt{8}}{8}

    So,

    \frac{\sqrt{24}}{8}

    Then if you need to simplify, you can factor out 3 (since 3 x 3 x 3 = 24) giving you:

    \frac{3\sqrt{3}}{8}




    3√[16] rasied dot 3√[3]


    Thank you so much

    Please note that on the second question the 3's are the indexs
    Not sure what you have here, is it \sqrt[3]{16}\cdot \sqrt[3]{3} ??
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  3. #3
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    Quote Originally Posted by mollymcf2009 View Post
    Change this to:

    \frac{\sqrt{3}}{\sqrt{8}}

    Since you want to get rid of the square root in the denominator, multiply the top and bottom by \sqrt{8} giving:

    \frac{\sqrt{3}\sqrt{8}}{8}

    So,

    \frac{\sqrt{24}}{8}

    Then if you need to simplify, you can factor out 3 (since 3 x 3 x 3 = 24) giving you:

    \frac{3\sqrt{3}}{8}




    Not sure what you have here, is it \sqrt[3]{16}\cdot \sqrt[3]{3} ??

    TThanks for the help on the first one and yes on the second
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  4. #4
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by mr_quick View Post
    TThanks for the help on the first one and yes on the second
    Well, \sqrt[3]{16} \cdot \sqrt[3]{3} = \sqrt[3]{48}

    =\sqrt[3]{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}

    = 2\sqrt[3]{6}

    If you are supposed to get a non-radical answer, use a calculator. You can calculate a cubed root of a number by raising that number to \frac{1}{3}
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  5. #5
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    Quote Originally Posted by mollymcf2009 View Post
    Well, \sqrt[3]{16} \cdot \sqrt[3]{3} = \sqrt[3]{48}

    =\sqrt[3]{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}

    = 2\sqrt[3]{6}

    If you are supposed to get a non-radical answer, use a calculator. You can calculate a cubed root of a number by raising that number to \frac{1}{3}
    Thank you so much you are a life saver
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