Can someone please help me with these radicals

√[3/8]

3√[16] rasied dot 3√[3]

Thank you so much

Please note that on the second question the 3's are the indexs

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- May 14th 2009, 06:15 PMmr_quickNeed more help with radicals
Can someone please help me with these radicals

√[3/8]

3√[16] rasied dot 3√[3]

Thank you so much

Please note that on the second question the 3's are the indexs - May 14th 2009, 06:42 PMmollymcf2009
Change this to:

$\displaystyle \frac{\sqrt{3}}{\sqrt{8}}$

Since you want to get rid of the square root in the denominator, multiply the top and bottom by $\displaystyle \sqrt{8}$ giving:

$\displaystyle \frac{\sqrt{3}\sqrt{8}}{8}$

So,

$\displaystyle \frac{\sqrt{24}}{8}$

Then if you need to simplify, you can factor out 3 (since 3 x 3 x 3 = 24) giving you:

$\displaystyle \frac{3\sqrt{3}}{8}$

Quote:

3√[16] rasied dot 3√[3]

Thank you so much

Please note that on the second question the 3's are the indexs

- May 14th 2009, 07:04 PMmr_quick
- May 14th 2009, 07:57 PMmollymcf2009
Well, $\displaystyle \sqrt[3]{16} \cdot \sqrt[3]{3}$ = $\displaystyle \sqrt[3]{48} $

$\displaystyle =\sqrt[3]{2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}$

$\displaystyle = 2\sqrt[3]{6}$

If you are supposed to get a non-radical answer, use a calculator. You can calculate a cubed root of a number by raising that number to $\displaystyle \frac{1}{3}$ - May 14th 2009, 08:24 PMmr_quick