Results 1 to 4 of 4

Math Help - radical problem

  1. #1
    Newbie
    Joined
    May 2009
    Posts
    2

    radical problem

    I am 42 years young and trying to brush up my 25 year old shelved algebra knowledge.

    I am stumped with this problem.
    I have the answer, but I don't know how to get there exactly. I know I will have to square both sides and that it will wind up as a Quad equation, but I am sooo lost on how to get there.

    Please help! Thanks!

    <br />
4\sqrt{x-1}+1=x<br />
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    May 2009
    Posts
    7
    4rt(x-1)=x-1

    squaring gives

    16(x-1)=(x-1)(x-1)

    gives x^2 -18x +17

    factorise gives x=17 x=1

    hope this helps.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Math Engineering Student
    Krizalid's Avatar
    Joined
    Mar 2007
    From
    Santiago, Chile
    Posts
    3,654
    Thanks
    13
    let x\ge1, thus 4\sqrt{x-1}=x-1, which is equal to \sqrt{x-1}\left( 4-\sqrt{x-1} \right)=0 and from here it's \sqrt{x-1}=0\implies x=1 or \sqrt{x-1}=4\implies x=17.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    May 2009
    Posts
    2
    Thank you, thank you! I was missing the swing of the 16 and 16x!
    I have finished the problem!

    Thank you again, both of you!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. radical equation problem help
    Posted in the Algebra Forum
    Replies: 1
    Last Post: August 13th 2011, 04:57 PM
  2. Radical problem.
    Posted in the Algebra Forum
    Replies: 2
    Last Post: March 9th 2010, 03:05 PM
  3. question about radical problem
    Posted in the Algebra Forum
    Replies: 7
    Last Post: October 2nd 2009, 12:53 PM
  4. Radical problem
    Posted in the Math Topics Forum
    Replies: 4
    Last Post: February 25th 2009, 01:42 PM
  5. Help with radical problem
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: January 25th 2006, 11:29 AM

Search Tags


/mathhelpforum @mathhelpforum