But why don't you want to use the quadratic formula ?
The roots of are
that's much simpler !
(I tried to do it by completing the square, and that was quite useless)
Solve Algebraically - These Simultaneous equations.y=3x-2Here is what I've done so far, please correct me if i'm wrong as always.x^2+y^2=20Can anyone solve this without using the quadratic equation? Many Thanks!x^2+(3x-2)(3x-2)=20 x^2+9x^2-6x-6x-16=0 10x^2-12x-16=0
Look at the factors of 10: 1 & 10, 2 & 5, 2.5 & 4, 3 & 3 1/3 etc
then the factors of -12: 1 & 12, 2 & 6, 3 & 4, etc
then the factors of -16: 1 & 16, 2 & 8,
If you are logical & systematic, you can reduce the total amount of trials required to arrive at a workable solution.
With a little work you'll end with (2x-4)*(5x+4)
Then solve for each x within the parentheses:
5x+4 = 0
5x = -4
x = -4/5
Why not use the quadratic formula?